COMPLEX ANALYSIS GENERAL EXAM JANUARY 2025

Solve as many problems as you can. Full solutions on a smaller number of problems will be worth more than partial solutions on several problems. Don’t use any of the Picard theorems. Throughout, 𝔻\mathbb{D} denotes the unit disc {z:|z|<1}\{z \in \mathbb{C}:|z|<1\}.

Problem 1

Let f:𝔻¯f: \overline{\mathbb{D}} \rightarrow \mathbb{C} be a continuous function for which f|𝔻\left.f\right|_{\mathbb{D}} is holomorphic and |f(z)|=1|f(z)|=1 for all z𝔻z \in \partial \mathbb{D}. Show that that there exists a finite collection of points z1,…,zn𝔻z_{1}, \ldots, z_{n} \in \mathbb{D} and some θ\theta \in \mathbb{R} such that

f(z)=eiθj=1nzjβˆ’z1βˆ’zjΒ―zf(z)=e^{i \theta} \prod_{j=1}^{n} \frac{z_{j}-z}{1-\overline{z_{j}} z}

Problem 2

Let f:{2,3}f: \mathbb{C} \backslash\{2,3\} \rightarrow \mathbb{C} be the holomorphic function

f(z):=z(zβˆ’2)(zβˆ’3)f(z):=\frac{z}{(z-2)(z-3)}

For each of the following regions, determine the Laurent series of ff that converges on the given region.
(a) {z:|z|<2}\{z \in \mathbb{C}:|z|<2\}
(b) {z:2<|z|<3}\{z \in \mathbb{C}: 2<|z|<3\}
(c) {z:|z|>3}\{z \in \mathbb{C}:|z|>3\}

Problem 3

Let u:2u: \mathbb{R}^{2} \rightarrow \mathbb{R} be a harmonic function, and suppose that u(x,y)xu(x, y) \leq x for all (x,y)2(x, y) \in \mathbb{R}^{2}. Show that there exists a constant c(βˆ’,0]c \in(-\infty, 0] such that u(x,y)=x+cu(x, y)=x+c for all (x,y)2(x, y) \in \mathbb{R}^{2}.

Problem 4

Using Cauchy's residue theorem, show that for a,ba, b \in \mathbb{R} with 0<b<a0<b<a,

02π1(a+bsinθ)2dθ=2πa(a2βˆ’b2)3/2\int_{0}^{2 \pi} \frac{1}{(a+b \sin \theta)^{2}} d \theta=\frac{2 \pi a}{\left(a^{2}-b^{2}\right)^{3 / 2}}

Problem 5

(a) Let f:𝔻𝔻f: \mathbb{D} \rightarrow \mathbb{D} be a holomorphic function satisfying f(0)=23f(0)=\frac{2}{3}. Show that |fβ€²(0)|59\left|f^{\prime}(0)\right| \leq \frac{5}{9}.
(b) Determine all holomorphic functions f:𝔻𝔻f: \mathbb{D} \rightarrow \mathbb{D} that simultaneously satisfy both f(0)=23f(0)=\frac{2}{3} and |fβ€²(0)|=59\left|f^{\prime}(0)\right|=\frac{5}{9}.