4.1 Dual spaces and bilinear forms
Know the basic definitions: Linear form (or functional), dual space (space of all linear forms), dual basis (to a basis for ); annihilator (of a subset of in ); dual (or adjoint or transpose) of a linear transformation (defined by for ); Bilinear form on (bilinear map ) left and right duality maps (via symmetric, alternating, skew symmetric, nondegenerate, anisotropic ( ) bilinear form. Orthogonal direct sum , isometry of spaces with bilinear forms, orthogonal (isometry ). Symplectic plane for an alternate bilinear form (basis with , hence ).
Definitions for a given Bilinear Form Matrix of relative to an ordered basis of ; left and right annihilators (or orthogonal complements) of a subspace (the vectors killing from the left or right, or 0 ), left and right radical , left, right orthogonality, orthosymmetric ; standard examples: symmetric and alternating forms). Isotropic vector .
Know Facts:
(1)
linear map
or
gives
or
gives
or
;
(2) IF
IS FIN. DIM., nondegenerate bilinear form on
isomorphism (
or
)
;
a bilinear form
is nondegenerate
left nondegenerate (left radical zero)
right nondegenerate (right radical zero)
some/any matrix of
is invertible (
),
for the change-of-basis matrix
the discriminant
is a well-defined invariant of
;
it is zero iff
is degenerate.
(3) If
is again finite-dimensional and
a nondegenerate symmetric bilinear form, we may identify
with
via
,
i.e. we may identify each
with
(since
is symmetric,
). Making this identification, any endomorphism of
can also be interpreted as an endomorphism of
.
Then the dual
of an endomorphism
of
is characterized by the following property:
for all
.
Basic Splitting Lemma: If
is orthosymmetric, any finite-dimensional nondegenerate subspace
of
is an orthogonal direct summand,
.
Basic Structure Theorems:
(I) Any space with alternating form
is a direct sum
for
the radical,
symplectic planes. Therefore, the rank of any matrix representing
is even and its determinant is a square. In particular, there are no
nondegenerate alternating forms in odd dimensions.
(II) Any vector space over a field
with
with symmetric form is a direct sum
for
the radical,
anisotropic lines (
with
); thus there is an orthogonal basis
relative to which
has diagonal matrix. Over an algebraically closed field, we can assume
all
;
over the reals, we can assume all
,
with the numbers of +1 ’s, -1 ’s, and 0 ’s being invariants of
by Sylvester’s Law of Inertia.
Related Problems
(Aug ) If is an alternating bilinear form on a 25 -dimensional real vector space, and is its matrix with respect to some basis, show that .
(Aug 95 #7) Show that every element of and [where is the usual dot product on ] has a nonzero fixed point .
(Aug ) It is easy to check that the space of real matrices is a real inner product space with inner product given by: , where denotes the transpose of the matrix . Let be an invertible matrix and the linear operator on defined by . Denote the adjoint of relative to this inner product by . Prove that for all , and find necessary and sufficient conditions on the matrix that . Justify your answer.
(Jan ) Let be a finite-dimensional vector space over a field , and let and be two linear functionals on . Define for . Show that is an alternating bilinear form on , and determine the possible values for its rank.
(Jan ) Define the trace of an real matrix, and show that the trace of the product of two real matrices is the same as the trace of .
(b) Explain why the trace of such a matrix is the sum of all eigenvalues (possibly complex, with the appropriate multiplicities) of the matrix.
(b) Explain how you would define the trace of an abstract linear operator on any finitedimensional real vector space (i.e., a linear transformation from to ).(Jan ) Let be a field and the matrices over .
(a) Determine all linear functionals which are symmetric in the sense that for all matrices .
(b) Determine all linear functionals which are invariant in the sense that for all invertible .(Aug ) Let be a symmetric bilinear form on a finite-dimensional vector space over a field . For a subspace , we define the annihilator subspace of in : for every . Assume further that is nondegenerate, that is . Show that:
(a) there is a natural isomorphism of vector spaces from to the dual space of ;
(b) ;
(c) .(Jan 19 #4) Let be a field with , let be a finite-dimensional vector space over , and let be a symmetric bilinear form on .
(a) Prove that if , there exists such that .
(b) Prove that for any with there exists a subspace such that and , that is, for all .
(c) Use (a) and (b) to prove that there is a basis of such that for all .