3.1 Modules

Know basic notions:

(i) for a general, not necessarily commutative ring RR :
RR-module, submodule, quotient module, isomorphism theorem(s), correspondence theorem; annihilators and torsion elements; cyclic, simple (or irreducible) and free modules; direct sums and direct products and their universal properties; know that the direct product of infinitely many copies of \mathbb{Z} is not a free \mathbb{Z}-module; spanning and linearly independent subsets; sets of RR-module homomorphisms and the algebraic structures on them: HomR(M,N)\operatorname{Hom}_{R}(M, N) is always an abelian group and an RR-module if RR is commutative; EndR(M)=HomR(M,M)\operatorname{End}_{R}(M)=\operatorname{Hom}_{R}(M, M) is always a ring and an RR-algebra if RR is commutative; know that EndR(Rn)\operatorname{End}_{R}\left(R^{n}\right) is isomorphic to Mn(R)M_{n}(R) if RR is commutative;
(ii) for an integral domain RR : torsion submodule; well-defined rank of a free RR-module; know that submodules of free modules need not be free but that rk MrkMM^{\prime} \leq \operatorname{rk} M if MM^{\prime} is a free submodule of a free module MM.

Know the basic theorems for finitely generated modules over a PID RR : submodules of a free RR-module MM are free (this is also true if MM is not finitely generated); torsion free finitely generated RR-modules are free; a finitely generated RR-module MM is always the direct some of its torsion submodule T(M)T(M) and a free (finitely generated) submodule, and T(M)T(M) is a finite direct sum of cyclic modules; existence and uniqueness of invariant factors and elementary divisors, namely (see also Section 1.3):

Elementary Divisor Form (longest decomposition into cyclics): Any finitely generated RR-module MM can be written as M=R/(p1e1)R/(prer)RnM=R /\left(p_{1}^{e_{1}}\right) \oplus \ldots R /\left(p_{r}^{e_{r}}\right) \oplus R^{n}, where nn is the rank of M/T(M)M / T(M), the pip_{i} are (not necessarily distinct) prime elements of RR, determined up to multiplication with units by MM, and the eie_{i} are natural numbers, also uniquely determined by MM (up to possible permutations of the direct summands). The prime powers piei(1ir)p_{i}^{e_{i}}(1 \leq i \leq r) are called the elementary divisors of MM.

Invariant Factor Form (shortest decomposition into cyclics): M=R/(d1)R/(ds)RnM=R /\left(d_{1}\right) \oplus \ldots R /\left(d_{s}\right) \oplus R^{n} with nn as before and elements diR(R*{0})d_{i} \in R \backslash\left(R^{*} \cup\{0\}\right) satisfying d1|d2|dsd_{1}\left|d_{2} \ldots\right| d_{s}. These elements did_{i} are, up to multiplication with units, uniquely determined by MM and called the invariant factors of MM.
(Side remark: The number nn is often called the Betti number of MM.)
Know the "Compatible Basis Theorem": If NN is a submodule of a finitely generated free RR-module M(RM(R a PID )), then there exist an RR-basis y1,,yny_{1}, \ldots, y_{n} of MM and elements diR{0}d_{i} \in R \backslash\{0\} ( 1is1 \leq i \leq s ), up to multiplication with units uniquely determined by MM and NN and called the invariant factors of NN with respect to MM, such that d1|d2|dsd_{1}\left|d_{2} \ldots\right| d_{s} and d1y1,,dsysd_{1} y_{1}, \ldots, d_{s} y_{s} is an RR-basis of NN.

Know How to Decompose if RR is Euclidean:

(I) Write M=F/NM=F / N for FF free on nn generators {y1,,yn}\left\{y_{1}, \ldots, y_{n}\right\}, and choose (not necessarily free) generators ci1y1+cinyn,i=1,,mc_{i 1} y_{1}+\ldots c_{i n} y_{n}, i=1, \ldots, m for NN (in other words: ci1y1+cinyn=0c_{i 1} y_{1}+\ldots c_{i n} y_{n}=0 with i=1,,mi=1, \ldots, m is a set of defining relations for MM ). Define the relations matrix C=(cij)C=\left(c_{i j}\right).
(II) Now apply elementary row and column operations operations to CC until you reach a diagonal form diag(d1,,ds)\operatorname{diag}\left(d_{1}, \ldots, d_{s}\right) with diR{0}d_{i} \in R \backslash\{0\} and d1|d2|dsd_{1}\left|d_{2}\right| \ldots \mid d_{s}, meaning that the resulting matrix has d1,,dsd_{1}, \ldots, d_{s} as its first ss entries on the main diagonal and zeros everywhere else (the Euclidean Algorithm guarantees that this is possible).
(III) Then the did_{i} ’s which are no units are the invariant factors of MM, and MM is isomorphic to diR*R/(di)Rns\bigoplus_{d_{i} \notin R^{*}} R /\left(d_{i}\right) \oplus R^{n-s}. Keeping track of the column operations, this procedure also yields compatible bases for MM and NN, implying that d1,,dsd_{1}, \ldots, d_{s} (including the units) are the invariant factors of NN with respect to FF.

  1. (Sep 82#282 \# 2 ) If a1,,ana_{1}, \ldots, a_{n} in a PID RR have gcdd\operatorname{gcd} d, show that there exists an invertible n×nn \times n matrix QQ of determinant 1 over RR with Q[a1,,an]T=[d,0,00]TQ\left[a_{1}, \ldots, a_{n}\right]^{T}=[d, 0,0 \ldots 0]^{T}. (This is false if RR is merely a UFD).

  2. (Sep 84#584 \# 5 ) If A,B,CA, B, C are submodules of a general RR-module MM, with ACA \supseteq C, show A(B+C)=(AB)+CA \cap(B+ C)=(A \cap B)+C.

  3. (Sep 84 #6) Find the invariant factors of the following 3×33 \times 3 matrices over \mathbb{Z}, and decide if they are equivalent: (1000040006),(4644201220020)\left(\begin{array}{ccc}10 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 6\end{array}\right),\left(\begin{array}{ccc}4 & 6 & 4 \\ 4 & 20 & 12 \\ 20 & 0 & 20\end{array}\right).

  4. (Sept 86#586 \# 5 ) If MM is an artinian module over a general RR, show that any injective endomorphism is surjective.
    (A module MM over a general ring RR is called artinian if there is no infinite chain of strictly decreasing submodules of MM. Standard example (explain why this is an example!): R=R= finite dimensional KK-algebra for a field KK and M=M= finitely generated RR-module.)

  5. (Jan 87 #6; Aug 88 #6) If II is an ideal of a commutative ring RR, show
    (a) R/IR / I is simple as an RR-module I\Longleftrightarrow I is a maximal ideal,
    (b) II prime R/I\Longrightarrow R / I is an indecomposable RR-module;
    (An RR-module is called indecomposable if it cannot be written as the direct sum of two nonzero RR-modules.)
    (c) if II is prime, what kind of ring is R/IR / I ?

  6. (May 91#691 \# 6 ) Let M=M=\mathbb{Z} \oplus \mathbb{Z} be the free module of rank 2 over the ring \mathbb{Z} of integers. Let SS be the submodule of MM spanned by x=(3,0),y=(0,4),z=(6,2)x=(3,0), y=(0,4), z=(6,2). Find a \mathbb{Z}-basis for the submodule SS.

  7. (Aug 94 #8) If the annihilator of a left RR-module MM is AnnR(M)={aRaM=0}A n n_{R}(M)=\{a \in R \mid a M=0\}, show that for submodules M1,M2M_{1}, M_{2} of MM we have AnnR(M1+M2)=AnnR(M1)AnnR(M2)A n n_{R}\left(M_{1}+M_{2}\right)=A n n_{R}\left(M_{1}\right) \cap A n n_{R}\left(M_{2}\right). Show furthermore that we have AnnR(M1)+AnnR(M2)AnnR(M1M2)A n n_{R}\left(M_{1}\right)+A n n_{R}\left(M_{2}\right) \subseteq A n n_{R}\left(M_{1} \cap M_{2}\right), but show that this inclusion could be strict.
    Additional question: Is AnnR(M1)+AnnR(M2)=AnnR(M1M2)A n n_{R}\left(M_{1}\right)+A n n_{R}\left(M_{2}\right)=A n n_{R}\left(M_{1} \cap M_{2}\right) true if RR is a PID and MM is a finitely generated torsion RR-module (no free summand)?

  8. (Aug 96#396 \# 3 ) Let MM be a finitely generated module over a ring RR. Show that any generating set for MM as RR-module must contain a finite generating set. Conclude that MM has a minimal generating set (no proper subset generates MM ), and that every minimal generating set of MM is finite.

  9. (Aug 97#797 \# 7 ) Let MM be the free module over [x]\mathbb{Q}[x] with basis v1,v2,v3,Nv_{1}, v_{2}, v_{3}, N a submodule with basis w1,w2,w3w_{1}, w_{2}, w_{3}, where

w1=(x3x2x+1)v1+(2x2+2x)v2+(x3+x2)v3w2=(2x33x23x+2)v1+(5x2+5x)v2+(2x3+2x2)v3w3=(x3x)v1+(x2+x)v2+(x3+x2)v3\begin{aligned} & w_{1}=\left(x^{3}-x^{2}-x+1\right) v_{1}+\left(2 x^{2}+2 x\right) v_{2}+\left(x^{3}+x^{2}\right) v_{3} \\ & w_{2}=\left(2 x^{3}-3 x^{2}-3 x+2\right) v_{1}+\left(5 x^{2}+5 x\right) v_{2}+\left(2 x^{3}+2 x^{2}\right) v_{3} \\ & w_{3}=\left(x^{3}-x\right) v_{1}+\left(x^{2}+x\right) v_{2}+\left(x^{3}+x^{2}\right) v_{3} \end{aligned}

(a) There is a theorem which implies that MM has another basis u1,u2,u3u_{1}, u_{2}, u_{3} for which d1u1,d2u2,d3u3d_{1} u_{1}, d_{2} u_{2}, d_{3} u_{3} are a basis for NN for some d1,d2,d3[x]d_{1}, d_{2}, d_{3} \in \mathbb{Q}[x] such that d1|d2|d3d_{1}\left|d_{2}\right| d_{3}. Write a carefully worded statement of this theorem, giving all appropriate hypotheses and conclusions.
(b) Find the values d1,d2,d3d_{1}, d_{2}, d_{3} for the example given here.
10. (Jan 98 #4) Let MM be a module over a ring. A section A:BA: B of MM is a pair of submodules A,BA, B of MM with BAB \subseteq A; a trivial section is where B=AB=A. A submodule CC of MM covers a section A:BA: B if (AC)+B=A(A \cap C)+B=A, and avoids A:BA: B if ACBA \cap C \subseteq B.
(a) Show that CC covers A:BA: B iff AB+CA \subseteq B+C, and avoids A:BA: B iff A(B+C)=BA \cap(B+C)=B.
(b) Show that every CC simultaneously covers and avoids any trivial section; that any CC with CAC \supseteq A covers A:B;A: B ; and that any CC with CBC \subseteq B avoids A:BA: B.
(c) Give an example of a \mathbb{Z}-module MM and a submodule CC that covers one nontrivial section A:BA: B and avoids another nontrivial section A:BA^{\prime}: B^{\prime} for which the two quotients A/BA / B and A/BA^{\prime} / B^{\prime} are isomorphic.
11. (Jan 05#305 \# 3 ) Let RR be a PID, pp a prime element of RR and M{0}M \neq\{0\} a finitely generated RR-module such that there exists a natural number kk with pkM={0}p^{k} M=\{0\}. We choose kk minimal
with this property, i.e. pk1M{0}p^{k-1} M \neq\{0\}.
(a) Describe the structure of MM. Show that pkp^{k} is an elementary divisor of MM and that each elementary divisor of MM divides pkp^{k}.
(b) Let mm be any element of MM with the property that pk1m0p^{k-1} m \neq 0. Show that the cyclic module N:=RmN:=R m has a complement CC in MM, i.e. M=NCM=N \oplus C.
12. (Jan 08 #2) (a) Let RR be a commutative ring with 1 , and MM a finite direct sum M=M1MnM= M_{1} \oplus \cdots \oplus M_{n} of simple unital left RR-modules MiM_{i}. Show that MM has both the ascending and descending chain conditions on RR-submodules.
(b) Where does your argument use the hypotheses that RR is unital, RR is commutative, or MM is unital?
13. (Aug 11#311 \# 3 ) (a) Let VV be an noetherian module for a ring RR, so that VV satisfies the ascending chain condition on submodules. Let T:VVT: V \rightarrow V be a surjective RR-endomorphism. Prove that TT is an isomorphism.
(b) In (a) suppose that RR is a field, so VV is a vector space. Give another explanation of (a) in terms of the rank and nullity of TT.
14. (Jan 12#612 \# 6 ) Let RR be a commutative ring with 1 . Recall that a left R -module MM is called Noetherian if it satisfies the ascending chain condition on submodules and Artinian if it satisfies the descending chain condition on submodules. Assume that an RR-module MM is both Artinian and Noetherian. (For example, RR might be a field, and MM might be a finitedimensional vector space over RR ). Let T:MMT: M \rightarrow M be an RR-module homomorphism.
(a) Prove that there exists kk \in \mathbb{N} s.t. Ker(Tk)=Ker(T2k)\operatorname{Ker}\left(T^{k}\right)=\operatorname{Ker}\left(T^{2 k}\right) and Im(Tk)=Im(T2k)\operatorname{Im}\left(T^{k}\right)=\operatorname{Im}\left(T^{2 k}\right).
(b) Prove that if kk is as in part (a), then M=Ker(Tk)Im(Tk)M=\operatorname{Ker}\left(T^{k}\right) \oplus \operatorname{Im}\left(T^{k}\right).
(c) Deduce from (a) and (b) that there exist submodules M0M_{0} and M1M_{1} of MM s.t. M=M0M1M=M_{0} \oplus M_{1}, TM0T_{\mid M_{0}} is nilpotent and TM1T_{\mid M_{1}} is invertible (as a map from M1M_{1} to M1M_{1} ).
(d) Now assume that RR is a field of characteristic zero, MM is a finite-dimensional vector space over RR and tr(Tn)=0\operatorname{tr}\left(T^{n}\right)=0 for every n>0n \in \mathbb{Z}_{>0}. Prove that TT is nilpotent. Hint: Apply (c), assume that M10M_{1} \neq 0 and reach a contradiction by applying the Cayley-Hamilton theorem to TM1T_{\mid M_{1}}.
15. (Aug 15#515 \# 5 ) Let RR be a commutative ring with identity, and let II be a nilpotent ideal, i.e., Ik=0I^{k}=0 for some kk. Let M,NM, N be two RR-modules, and let f:MNf: M \rightarrow N be an RR-homomorphism. Suppose that the induced homomorphism from M/IMM / I M to N/INN / I N is surjective. Prove that ff is surjective.
16. (Jan 16#316 \# 3 ) Let R be a commutative ring with identity. A non-zero RR-module MM is said to be irreducible if 0 and MM are the only submodules of MM. Prove that MM is irreducible if and only if MR/mM \cong R / m, where mm is a maximal ideal of RR.
17. (Aug 16 # 7)
(a)Give a complete and irredundant list of abelian groups of order 144.
(b)Give a complete and irredundant list of finitely generated modules over 𝔽2[t]\mathbb{F}_{2}[t] where the polynomial t4+t3+t+1t^{4}+t^{3}+t+1 acts trivially.
18. (Jan 17 #7) Consider the matrix

A=[124164378311]A=\left[\begin{array}{ccc} 12 & 4 & -16 \\ 4 & 3 & -7 \\ 8 & 3 & -11 \end{array}\right]

(a) Find the characteristic and minimal polynomials of this polynomial and its Jordan normal form.
(b) Consider map 33\mathbb{Z}^{3} \rightarrow \mathbb{Z}^{3} induced by AA. Describe the kernel and cokernel of this map as a sum of copies of \mathbb{Z} and /n\mathbb{Z} / n \mathbb{Z}.
19. (Aug 18 #4) Let RR be an integral domain and let MM be a nontrivial torsion RR-module.
(a) If MM is finitely generated then the annihilator of MM in RR is nontrivial. Recall that the annihilator of MM is the ideal {rrm=0\{r \mid r m=0 for all mM}m \in M\}.
(b) Find an integral domain RR and a torsion module MM over RR whose annihilator is the zero ideal.
20. (Jan 19#619 \# 6 ) Let RR be a commutative ring with 1 , let MM be an RR-module and NN a submodule of RR.
(a) Prove that if NN and M/NM / N are both finitely generated, then MM is finitely generated
(b) Give an example where MM is finitely generated and NN is not.
21. (Jan 20 #6) In each part of this problem determine if the given objects are isomorphic:
(a) \mathbb{R} and \mathbb{C} as \mathbb{Q}-vector spaces
(b) \mathbb{C} and ×\mathbb{R} \times \mathbb{R} as rings
(c) [x]/(x21)\mathbb{R}[x] /\left(x^{2}-1\right) and ×\mathbb{R} \times \mathbb{R} as rings
(d) [x]/(x1)\mathbb{R}[x] /(x-1) and [x]/(x+1)\mathbb{R}[x] /(x+1) as [x]\mathbb{R}[x]-modules
22. (Jan 22 #6) In each part determine whether the statement is TRUE (in all cases) or FALSE (in at least one case) and prove your claim. An answer (correct or incorrect) without explanation will not receive any credit.
(a) Let RR be a commutative domain with 1 and MM an RR-module. If xMx \in M and yMy \in M are both torsion elements, then x+yx+y is also a torsion element.
(b) If KK and LL are fields, then KLK \otimes_{\mathbb{Z}} L is nonzero.
(c) If RR is a commutative ring with 1 and every RR-module is free, then RR is a field.
(d) If RR is a commutative ring with 1 and MM is a finitely generated RR-module, then every submodule of MM is finitely generated.