Algebra general exam. January 9, 2013, 9am -1pm

Directions.

Problem 1

Let pp be a prime and let S2pS_{2 p} denote the symmetric group on 2p2 p elements.
(a) ( 2 pts) Find the order of a pp-Sylow subgroup of S2pS_{2 p}.
(b) ( 5 pts) Describe explicitly a pp-Sylow subgroup of S2pS_{2 p} (providing a generating set counts as explicit description, but make sure to prove that your subgroup is indeed pp-Sylow).
(c) ( 2 pts) Consider the set of elements of order pp in S2pS_{2 p} - clearly, it is a union of conjugacy classes. How many conjugacy classes does it consist of?
(d) ( 5 pts) Now consider the set of elements of order pp in the alternating group A2pA_{2 p}. How many conjugacy classes (of A2pA_{2 p} ) does it consist of? Make sure to justify your answer.
Hint: Distinguish between the cases p=2p=2 and p>2p>2.

Problem 2

In both parts of this problem RR is a commutative domain with 1 and KK is the field of fractions of RR.
(a) ( 5 pts) Let R=[t]R=\mathbb{Z}[t], the ring of polynomials over \mathbb{Z} in one variable. Let p(x)=xn+rn1xn1++r0R[x]p(x)=x^{n}+r_{n-1} x^{n-1}+\ldots+r_{0} \in R[x] be a monic polynomial with coefficients in RR, and suppose that p(α)=0p(\alpha)=0 for some αK\alpha \in K. Prove that αR\alpha \in R.
(b) (4 pts) Now let R=[3]R=\mathbb{Z}[\sqrt{-3}]. Find a monic polynomial p(x)R[x]p(x) \in R[x] which has a root in KK, but has no root in RR (and prove that p(x)p(x) has required properties). Hint: There actually exists a quadratic polynomial with integer coefficients with required property.

Problem 3

(6 pts) Let FF be a field, dd a positive integer, and f1,f2,F[x1,,xd]f_{1}, f_{2}, \ldots \in F\left[x_{1}, \ldots, x_{d}\right] an infinite sequence of polynomials in F[x1,,xd]F\left[x_{1}, \ldots, x_{d}\right]. Given a positive integer nn, let SnS_{n} be the set of all dd-tuples (a1,,ad)Fd\left(a_{1}, \ldots, a_{d}\right) \in F^{d} satisfying the following system of equations:

fi(a1,,ad)=0 for each 1in1 and fn(a1,,ad)=1.f_{i}\left(a_{1}, \ldots, a_{d}\right)=0 \text { for each } 1 \leq i \leq n-1 \text { and } f_{n}\left(a_{1}, \ldots, a_{d}\right)=1 .

Prove that there exists an integer NN such that the set SnS_{n} is empty for all nNn \geq N. Hint: Noetherian rings.

Problem 4

Let pp be a prime, 𝔽p\mathbb{F}_{p} a finite field of order pp, and let FF be a fixed algebraic closure of 𝔽p\mathbb{F}_{p}. For nn \in \mathbb{N}, denote by 𝔽pn\mathbb{F}_{p^{n}} the unique subfield of order pnp^{n} inside FF.
(a) ( 3 pts) Prove that 𝔽pn𝔽pm\mathbb{F}_{p^{n}} \cup \mathbb{F}_{p^{m}} is a subfield if and only if mm divides nn or nn divides mm.
(b) ( 4 pts ) For a subset SS of \mathbb{N}, let

F(S)=nS𝔽pnF(S)=\bigcup_{n \in S} \mathbb{F}_{p^{n}}

Give an example (with proof) of an infinite set SS for which F(S)F(S) is a subfield and F(S)FF(S) \neq F.

Problem 5

Let ω=e2πi/3\omega=e^{2 \pi i / 3} and consider the field K=(23,ω)K=\mathbb{Q}(\sqrt[3]{2}, \omega).
(a) (2 pts) Prove that [K:]=6[K: \mathbb{Q}]=6.
(b) ( 2 pts) Prove that K/K / \mathbb{Q} is a Galois extension.
(c) ( 3 pts) Let M/LM / L be any finite Galois extension. Prove that an element γM\gamma \in M is primitive for M/LM / L (that is, L(γ)=ML(\gamma)=M ) if and only if σ(γ)γ\sigma(\gamma) \neq \gamma for any σGal(M/L){1}\sigma \in \operatorname{Gal}(M / L) \backslash\{1\}.
(d) (4 pts) Now prove that γ=23+ω\gamma=\sqrt[3]{2}+\omega is a primitive element for K/K / \mathbb{Q}.
(e) ( 3 pts) Let x6+a5x5++a0x^{6}+a_{5} x^{5}+\ldots+a_{0} be the minimal polynomial of γ\gamma over \mathbb{Q}. Prove that a5=3a_{5}=3 without actually computing the minimal polynomial.

Problem 6

Let FF be an algebraically closed field and AMatn(F)A \in \operatorname{Mat}_{n}(F) an n×nn \times n matrix over FF for some n2n \geq 2.
(a) ( 6 pts) Prove that there exist a diagonalizable matrix DD and a nilpotent matrix NN (that is, Nk=0N^{k}=0 for some kk \in \mathbb{N} ) such that A=D+NA=D+N and DD and NN commute, that is, DN=NDD N=N D.
(b) ( 4 pts) Assume that AA itself is diagonalizable. Prove that if DD and NN satisfy the conditions of part (a), then N=0N=0 (and hence D=AD=A ). Hint: You may use the following fact without proof: if two diagonalizable matrices XX and YY commute, then they are simultaneously diagonalizable, that is, there exists an invertible matrix QQ such that Q1XQQ^{-1} X Q and Q1YQQ^{-1} Y Q are both diagonal.