In a pure orthogonal turning by a zero rake angle single point carbide cutting tool, the shear force has been computed to be $\text{400 N}$. The cutting velocity, $V_{c}=100$ $\text{m/min}$, depth of cut, $\text{t= 2.0 mm}$, feed, $s_{0}=0.1 \text{ mm}$/ ... $\text{m/min}$, the shear strength, $\tau_{s}$, of the material will be ______ $\text{MPa} (\textit{round off to two decimal places}$).

asked
Mar 1
in Others
jothee
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